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Problems
Contests
National and Regional Contests
Indonesia Contests
Indonesia Juniors
2011 Indonesia Juniors
2011 Indonesia Juniors
Part of
Indonesia Juniors
Subcontests
(2)
day 2
1
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Indonesia Juniors 2011 day 2 OSN SMP - Tic Tac Toe game for p2
p1. Given a set of
n
n
n
the first natural number. If one of the numbers is removed, then the average number remaining is
21
1
4
21\frac14
21
4
1
. Specify the number which is deleted. p2. Ipin and Upin play a game of Tic Tac Toe with a board measuring
3
×
3
3 \times 3
3
×
3
. Ipin gets first turn by playing
X
X
X
. Upin plays
O
O
O
. They must fill in the
X
X
X
or
O
O
O
mark on the board chess in turn. The winner of this game was the first person to successfully compose a sign horizontally, vertically, or diagonally. Determine as many final positions as possible, if Ipin wins in the
4
4
4
th step. For example, one of the positions the end is like the picture on the side. https://cdn.artofproblemsolving.com/attachments/6/a/a8946f24f583ca5e7c3d4ce32c9aa347c7e083.png p3. Numbers
1
1
1
to
10
10
10
are arranged in pentagons so that the sum of three numbers on each side is the same. For example, in the picture next to the number the three numbers are
16
16
16
. For all possible arrangements, determine the largest and smallest values of the sum of the three numbers. https://cdn.artofproblemsolving.com/attachments/2/8/3dd629361715b4edebc7803e2734e4f91ca3dc.pngp4. Define
S
(
n
)
=
∑
k
=
1
n
(
−
1
)
k
+
1
,
k
=
(
−
1
)
1
+
1
1
+
(
−
1
)
2
+
1
2
+
.
.
.
+
(
−
1
)
n
+
1
n
S(n)=\sum_{k=1}^{n}(-1)^{k+1}\,\, , \,\, k=(-1)^{1+1}1+(-1)^{2+1}2+...+(-1)^{n+1}n
S
(
n
)
=
k
=
1
∑
n
(
−
1
)
k
+
1
,
k
=
(
−
1
)
1
+
1
1
+
(
−
1
)
2
+
1
2
+
...
+
(
−
1
)
n
+
1
n
Investigate whether there are positive integers
m
m
m
and
n
n
n
that satisfy
S
(
m
)
+
S
(
n
)
+
S
(
m
+
n
)
=
2011
S(m) + S(n) + S(m + n) = 2011
S
(
m
)
+
S
(
n
)
+
S
(
m
+
n
)
=
2011
p5. Consider the cube
A
B
C
D
.
E
F
G
H
ABCD.EFGH
A
BC
D
.
EFG
H
with side length
2
2
2
units. Point
A
,
B
,
C
A, B, C
A
,
B
,
C
, and
D
D
D
lie in the lower side plane. Point
I
I
I
is intersection point of the diagonal lines on the plane of the upper side. Next, make a pyramid
I
.
A
B
C
D
I.ABCD
I
.
A
BC
D
. If the pyramid
I
.
A
B
C
D
I.ABCD
I
.
A
BC
D
is cut by a diagonal plane connecting the points
A
,
B
,
G
A, B, G
A
,
B
,
G
, and
H
H
H
, determine the volume of the truncated pyramid low part.
day 1
1
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Indonesia Juniors 2011 day 1 OSN SMP
p1. From the measurement of the height of nine trees obtained data as following. a) There are three different measurement results (in meters) b) All data are positive numbers c) Mean
=
=
=
median
=
=
=
mode
=
3
= 3
=
3
d) The sum of the squares of all data is
87.
87.
87.
Determine all possible heights of the nine trees. p2. If
x
x
x
and
y
y
y
are integers, find the number of pairs
(
x
,
y
)
(x,y)
(
x
,
y
)
that satisfy
∣
x
∣
+
∣
y
∣
≤
50
|x|+|y|\le 50
∣
x
∣
+
∣
y
∣
≤
50
. p3. The plane figure
A
B
C
D
ABCD
A
BC
D
on the side is a trapezoid with
A
B
AB
A
B
parallel to
C
D
CD
C
D
. Points
E
E
E
and
F
F
F
lie on
C
D
CD
C
D
so that
A
D
AD
A
D
is parallel to
B
E
BE
BE
and
A
F
AF
A
F
is parallel to
B
C
BC
BC
. Point
H
H
H
is the intersection of
A
F
AF
A
F
with
B
E
BE
BE
and point
G
G
G
is the intersection of
A
C
AC
A
C
with
B
E
BE
BE
. If the length of
A
B
AB
A
B
is
4
4
4
cm and the length of
C
D
CD
C
D
is
10
10
10
cm, calculate the ratio of the area of the triangle
A
G
H
AGH
A
G
H
to the area of the trapezoid
A
B
C
D
ABCD
A
BC
D
. https://cdn.artofproblemsolving.com/attachments/c/7/e751fa791bce62f091024932c73672a518a240.png p4. A prospective doctor is required to intern in a hospital for five days in July
2011
2011
2011
. The hospital leadership gave the following rules: a) Internships may not be conducted on two consecutive days. b) The fifth day of internship can only be done after four days counted since the fourth day of internship. Suppose the fourth day of internship is the date
20
20
20
, then the fifth day of internship can only be carried out at least the date
24
24
24
. Determine the many possible schedule options for the prospective doctor. p5. Consider the following sequences of natural numbers:
5
5
5
,
55
55
55
,
555
555
555
,
5555
5555
5555
,
55555
55555
55555
,
.
.
.
...
...
,
5555...555555...
⏟
n
numbers
\underbrace{\hbox{5555...555555...}}_{\hbox{n\,\,numbers}}
n
numbers
5555...555555...
. The above sequence has a rule: the
n
n
n
th term consists of
n
n
n
numbers (digits)
5
5
5
. Show that any of the terms of the sequence is divisible by
2011
2011
2011
.