MathDB
Problems
Contests
National and Regional Contests
India Contests
Postal Coaching
2012 Postal Coaching
5
5
Part of
2012 Postal Coaching
Problems
(1)
Triangle Geometry
Source: Indian Postal Coaching 2012 Set 1 #5
9/19/2013
In triangle
A
B
C
ABC
A
BC
, \angle BAC = 94^{\circ},\ \angle ACB = 39^{\circ}. Prove that
B
C
2
=
A
C
2
+
A
C
ā
A
B
BC^2 = AC^2 + AC\cdot AB
B
C
2
=
A
C
2
+
A
C
ā
A
B
.
geometry
trigonometry
circumcircle
geometry unsolved