MathDB
Problems
Contests
National and Regional Contests
Greece Contests
Greece JBMO TST
2019 Greece JBMO TST
2
2
Part of
2019 Greece JBMO TST
Problems
(1)
solve in positive integers: 3 \cdot 2^x +4 =n^2
Source: Greece JBMO TST 2019 p2
4/29/2019
Find all pairs of positive integers
(
x
,
n
)
(x,n)
(
x
,
n
)
that are solutions of the equation
3
ā
2
x
+
4
=
n
2
3 \cdot 2^x +4 =n^2
3
ā
2
x
+
4
=
n
2
.
number theory
Diophantine equation
positive integers