MathDB

1

Part of 1982 Bundeswettbewerb Mathematik

Problems(2)

Bundeswettbewerb Mathematik 1982 Problem 1.1

Source: Bundeswettbewerb Mathematik 1982 Round 1

9/22/2022
Let SS be the sum of the greatest odd divisors of the natural numbers 11 through 2n2^n. Prove that 3S=4n+23S = 4^n + 2.
DivisorsSumnumber theory
Bundeswettbewerb Mathematik 1981 Problem 2.1

Source: Bundeswettbewerb Mathematik 1981 Round 2

9/22/2022
Max divided a natural number pp by a natural number q≤100q \leq 100. In the decimal representation of the quotient he calculated, the sequence of digits 19821982 occurs somewhere after the decimal point. Show that Max made a computational mistake.
divisordecimal representationalgebra