The Collatz's function is a mapping f:Z+→Z+ satisfying
f(x)=\begin{cases}
3x+1,& \mbox{as }x\mbox{ is odd}\\
x/2, & \mbox{as }x\mbox{ is even.}\\
\end{cases}
In addition, let us define the notation f1=f and inductively fk+1=f∘fk, or to say in another words, fk(x)=k timesf(…(f(x)…).Prove that there is an x∈Z+ satisfying f40(x)>2012x. functioninductionnumber theory unsolvednumber theory