Let ω be the circumcircle of an acute angled tirangle ABC. The line tangent to ω at A intersects the line BC at the point T. Let the midpoint of segment AT be N, and the centroid of △ABC be the point G. The other tangent line drawn from N to ω intersects ω at the point L. The line LG meets ω at S=L.
Prove that AS∥BC. geometryCentroidcircumcircle