Let △ABC be a triangle such that angle ∠ABC is less than angle ∠ACB. The bisector of angle ∠BAC cuts side BC at D. Let E be on side AB such that ∠EDB=90o and F on side AC such that ∠BED=∠DEF. Prove that ∠BAD=∠FDC. geometryangle bisectorequal anglesangles