MathDB

Problems(3)

Circle + triangle = hexagon ==> two parallel lines.

Source: Tuymaada 2002, day 1, problem 3. - Author : S. Berlov.

5/3/2007
A circle having common centre with the circumcircle of triangle ABCABC meets the sides of the triangle at six points forming convex hexagon A1A2B1B2C1C2A_{1}A_{2}B_{1}B_{2}C_{1}C_{2} (A1A_{1} and A2A_{2} lie on BCBC, B1B_{1} and B2B_{2} lie on ACAC, C1C_{1} and C2C_{2} lie on ABAB). If A1B1A_{1}B_{1} is parallel to the bisector of angle BB, prove that A2C2A_{2}C_{2} is parallel to the bisector of angle CC.
Proposed by S. Berlov
geometrycircumcircleincentergeometry proposed
trinomial with integer coefficients, and powers of two as natural values

Source: Tuymaada Junior 2002 p3

5/11/2019
Is there a quadratic trinomial with integer coefficients, such that all values which are natural to be natural powers of two?
algebrapolynomialInteger Polynomialtrinomialquadratic trinomialpower of 2
Acute triangle, circumcircle, isoceles triangle, altitudes.

Source: Tuymaada 2002, day 2, problem 3. - Author : D. Shiryaev.

5/3/2007
The points DD and EE on the circumcircle of an acute triangle ABCABC are such that AD=AE=BCAD=AE = BC. Let HH be the common point of the altitudes of triangle ABCABC. It is known that AH2=BH2+CH2AH^{2}=BH^{2}+CH^{2}. Prove that HH lies on the segment DEDE.
Proposed by D. Shiryaev
geometrycircumcircletrigonometrypower of a pointradical axisgeometry proposed