The altitudes of the acute-angled non-isosceles triangle ABC intersect at the point H. On the segment C1H, where CC1 is the altitude of the triangle, the point K is marked. Points L and M are the feet of perpendiculars from point K on straight lines AC and BC, respectively. The lines AM and BL intersect at N. Prove that ∠ANK=∠HNL. geometryAngle Chasingequal anglesaltitudes