2
Part of 2012 May Olympiad
Problems(2)
May Olympiad 2012, Level 2, Problem 2
Source:
8/24/2014
The vertices of two regular octagons are numbered from to , in some order, which may vary between both octagons (each octagon must have all numbers from to ). After this, one octagon is placed on top of the other so that every vertex from one octagon touches a vertex from the other. Then, the numbers of the vertices which are in contact are multiplied (i.e., if vertex has a number and is on top of vertex that has a number , then and are multiplied), and the products are then added.
Prove that, for any order in which the vertices may have been numbered, it is always possible to place one octagon on top of the other so that the final sum is at least .Note: the octagons can be rotated.
inequalitiesrotationgeometrygeometric transformation
sum of digits alternate's sum May Olympiad (Olimpiada de Mayo) 2012 L1 P2
Source:
9/30/2021
We call S the sum of the digits of the integer . For example, .
Find the value of
( has terms).
number theorysum of digits