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2001 JBMO ShortLists
7
7
Part of
2001 JBMO ShortLists
Problems
(1)
5-th powers is a no-go - JBMO Shortlist
Source:
10/30/2010
Prove that there are are no positive integers
x
x
x
and
y
y
y
such that
x
5
+
y
5
+
1
=
(
x
+
2
)
5
+
(
y
ā
3
)
5
x^5+y^5+1=(x+2)^5+(y-3)^5
x
5
+
y
5
+
1
=
(
x
+
2
)
5
+
(
y
ā
3
)
5
.[hide="Note"] The restriction
x
,
y
x,y
x
,
y
are positive isn't necessary.
modular arithmetic
number theory proposed
number theory