Let ABC be a fixed acute-angled triangle. Consider some points E and F lying on the sides AC and AB, respectively, and let M be the midpoint of EF . Let the perpendicular bisector of EF intersect the line BC at K, and let the perpendicular bisector of MK intersect the lines AC and AB at S and T , respectively. We call the pair (E,F) <spanclass=′latex−italic′>interesting</span>, if the quadrilateral KSAT is cyclic.
Suppose that the pairs (E1,F1) and (E2,F2) are interesting. Prove that ABE1E2=ACF1F2
Proposed by Ali Zamani, Iran IMO Shortlistgeometryhumpty point