MathDB

Problems(3)

Functional equation

Source: IMO Shortlist 2005 problem A4

3/12/2006
Find all functions f:RR f: \mathbb{R}\to\mathbb{R} such that f(x+y)+f(x)f(y)=f(xy)+2xy+1 f(x+y)+f(x)f(y)=f(xy)+2xy+1 for all real numbers x x and y y.
Proposed by B.J. Venkatachala, India
algebrafunctional equationIMO Shortlist
Labelling edges of a complete graph - maximal # of labels?

Source: IMO Shortlist 2005 Combinatorics problem C4; 5th German TST 2006, 23 April 2006, problem 1

12/29/2006
Let n3n\geq 3 be a fixed integer. Each side and each diagonal of a regular nn-gon is labelled with a number from the set {1;  2;  ...;  r}\left\{1;\;2;\;...;\;r\right\} in a way such that the following two conditions are fulfilled:
1. Each number from the set {1;  2;  ...;  r}\left\{1;\;2;\;...;\;r\right\} occurs at least once as a label.
2. In each triangle formed by three vertices of the nn-gon, two of the sides are labelled with the same number, and this number is greater than the label of the third side.
(a) Find the maximal rr for which such a labelling is possible.
(b) Harder version (IMO Shortlist 2005): For this maximal value of rr, how many such labellings are there?
[hide="Easier version (5th German TST 2006) - contains answer to the harder version"] Easier version (5th German TST 2006): Show that, for this maximal value of rr, there are exactly n!(n1)!2n1\frac{n!\left(n-1\right)!}{2^{n-1}} possible labellings.
Proposed by Federico Ardila, Colombia
functionIMO Shortlistgraph theorycombinatoricsExtremal combinatorics
Factorial: n!|a^n+1

Source: IMO Shortlist 2005 N4, Iran preparation exam

4/24/2006
Find all positive integers n n such that there exists a unique integer a a such that 0a<n! 0\leq a < n! with the following property: n!\mid a^n \plus{} 1
Proposed by Carlos Caicedo, Colombia
factorialmodular arithmeticnumber theoryDivisibilityexponentialIMO ShortlistChinese Remainder Theorem