7
Part of 1996 IMO Shortlist
Problems(3)
f(x + 13/42) + f(x) = f(x + 1/6) + f(x + 1/7)
Source: IMO Shortlist 1996, A7
8/9/2008
Let be a function from the set of real numbers into itself such for all we have and
f \left( x \plus{} \frac{13}{42} \right) \plus{} f(x) \equal{} f \left( x \plus{} \frac{1}{6} \right) \plus{} f \left( x \plus{} \frac{1}{7} \right).
Prove that is a periodic function (that is, there exists a non-zero real number such f(x\plus{}c) \equal{} f(x) for all ).
functionalgebrapolynomialfunctional equationIMO Shortlistperiodic function
Geometric Inequality
Source: IMO Shortlist 1996
9/29/2006
Let be an acute triangle with circumcenter and circumradius . meets the circumcircle of at , meets the circumcircle of at and meets the circumcircle of at . Prove that Sorry if this has been posted before since this is a very classical problem, but I failed to find it with the search-function.
inequalitiesgeometrycircumcircletrigonometrytrig identitiesIMO ShortlistTriangle
two injective surjective function
Source: ISL 1996, C7
6/6/2005
let be a finitive set and and be two injective surjective functions from to.let and be two sets such that they are defined as following"
S \equal{} \{w \in V: f(f(w)) \equal{} g(g(w))\}
T \equal{} \{w \in V: f(g(w)) \equal{} g(f(w))\}
we know that S \cup T \equal{} V, prove:
for each if and only if
functionsymmetrycombinatoricspartitionIMO Shortlist