In an acute-angled triangle ABC the interior bisector of angle A meets BC at L and meets the circumcircle of ABC again at N. From L perpendiculars are drawn to AB and AC, with feet K and M respectively. Prove that the quadrilateral AKNM and the triangle ABC have equal areas.(IMO Problem 2)Proposed by Soviet Union. geometrycircumcircletrigonometryarea of a triangleIMO Shortlist