Let pn(k) be the number of permutations of the set {1,2,3,…,n} which have exactly k fixed points. Prove that ∑k=0nkpn(k)=n!.(IMO Problem 1)Original formulation Let S be a set of n elements. We denote the number of all permutations of S that have exactly k fixed points by pn(k). Prove:(a) ∑k=0nkpn(k)=n! ; (b) ∑k=0n(k−1)2pn(k)=n!Proposed by Germany, FR probabilitycountingderangementpermutationsIMOIMO 1987IMO Shortlist