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1988 IMO Longlists
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92
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1988 IMO Longlists
Problems
(1)
Is there a lower boundary for a fraction sum inequality?
Source: IMO LongList 1988, Vietnam 4, Problem 92 of ILL
11/9/2005
Let
p
≥
2
p \geq 2
p
≥
2
be a natural number. Prove that there exist an integer
n
0
n_0
n
0
such that
∑
i
=
1
n
0
1
i
⋅
i
+
1
p
>
p
.
\sum^{n_0}_{i=1} \frac{1}{i \cdot \sqrt[p]{i + 1}} > p.
i
=
1
∑
n
0
i
⋅
p
i
+
1
1
>
p
.
inequalities
algebra unsolved
algebra