Let P be a set of n points and S a set of l segments. It is known that:
(i) No four points of P are coplanar.
(ii) Any segment from S has its endpoints at P.
(iii) There is a point, say g, in P that is the endpoint of a maximal number of segments from S and that is not a vertex of a tetrahedron having all its edges in S.
Prove that l≤3n2 inequalitiesgeometry3D geometrytetrahedrongeometry unsolved