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IberoAmerican
2015 İberoAmerican
2
2
Part of
2015 İberoAmerican
Problems
(1)
An angle bisector cuts a line at a point with a property
Source: 2015 Iberoamerican Olympiad. Problem 2
11/10/2015
A line
r
r
r
contains the points
A
A
A
,
B
B
B
,
C
C
C
,
D
D
D
in that order. Let
P
P
P
be a point not in
r
r
r
such that
∠
A
P
B
=
∠
C
P
D
\angle{APB} = \angle{CPD}
∠
A
PB
=
∠
CP
D
. Prove that the angle bisector of
∠
A
P
D
\angle{APD}
∠
A
P
D
intersects the line
r
r
r
at a point
G
G
G
such that:
1
G
A
+
1
G
C
=
1
G
B
+
1
G
D
\frac{1}{GA} + \frac{1}{GC} = \frac{1}{GB} + \frac{1}{GD}
G
A
1
+
GC
1
=
GB
1
+
G
D
1
geometry
angle bisector
Inversion