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Czech-Polish-Slovak Match
2000 Czech and Slovak Match
3
3
Part of
2000 Czech and Slovak Match
Problems
(1)
n power of 2 iff exists m so that 2^n-1 divides m^2 +9
Source: Czech and Slovak Match 2000 P3
10/1/2017
Let
n
n
n
be a positive integer. Prove that
n
n
n
is a power of two if and only if there exists an integer
m
m
m
such that
2
n
ā
1
2^n-1
2
n
ā
1
is a divisor of
m
2
+
9
m^2 +9
m
2
+
9
.
number theory
divisor
power of 2