MathDB
Problems
Contests
International Contests
Czech-Polish-Slovak Junior Match
2023 Czech-Polish-Slovak Junior Match
2023 Czech-Polish-Slovak Junior Match
Part of
Czech-Polish-Slovak Junior Match
Subcontests
(6)
6
1
Hide problems
area chasing in a rectangle
Given a rectangle
A
B
C
D
ABCD
A
BC
D
. Points
E
E
E
and
F
F
F
lie on sides
B
C
BC
BC
and
C
D
CD
C
D
respectively so that the area of triangles
A
B
E
ABE
A
BE
,
E
C
F
ECF
ECF
,
F
D
A
FDA
F
D
A
is equal to
1
1
1
. Determine the area of triangle
A
E
F
AEF
A
EF
.
5
2
Hide problems
S<- S+1/S
Bartek patiently performs operations on fractions. In each move, he adds its inverse to the current result, obtaining a new result. Bartek starts with the number
1
1
1
: after the first move, he receives the result 2, after the second move, the result is
5
2
\frac{5}{2}
2
5
, after the third move
29
10
\frac{29}{10}
10
29
, etc. After
300
300
300
moves, Bartek receives the result
x
x
x
. Determine the largest integer not greater than
x
x
x
.
x,y,z -> ..., xy + yz + zx = 1000, digits related
Mazo performs the following operation on triplets of non-negative integers: If at least one of them is positive, it chooses one positive number, decreases it by one, and replaces the digits in the units place with the other two numbers. It starts with the triple
x
x
x
,
y
y
y
,
z
z
z
. Find a triple of positive integers
x
x
x
,
y
y
y
,
z
z
z
such that
x
y
+
y
z
+
z
x
=
1000
xy + yz + zx = 1000
x
y
+
yz
+
z
x
=
1000
(*) and the number of operations that Mazo can subsequently perform with the triple
x
,
y
,
z
x, y, z
x
,
y
,
z
is(a) maximal (i.e. there is no triple of positive integers satisfying (*) that would allow him to do more operations);(b) minimal (i.e. every triple of positive integers satisfying (*) allows him to perform at least so many operations).
4
2
Hide problems
coloring 1x1 in a nxn array
Each field of the
n
×
n
n \times n
n
×
n
array has been colored either red or blue, with the following conditions met:
∙
\bullet
∙
if a row and a column contain the same number of red fields, the field at their intersection is red;
∙
\bullet
∙
if a row and a column contain different numbers of red cells, the field at their intersection is blue. Prove that the total number of blue cells is even.
2 tangents of different circles intersect on a line
In triangle
A
B
C
ABC
A
BC
, the points
M
M
M
and
N
N
N
are the midpoints of the sides
A
B
AB
A
B
and
A
C
AC
A
C
, respectively. The bisectors of interior angles
∠
A
B
C
\angle ABC
∠
A
BC
and
∠
B
C
A
\angle BCA
∠
BC
A
intersect the line
M
N
MN
MN
at points
P
P
P
and
Q
Q
Q
, respectively. Let
p
p
p
be the tangent to the circumscribed circle of the triangle
A
M
P
AMP
A
MP
passing through point
P
P
P
, and
q
q
q
be the tangent to the circumscribed circle of the triangle
A
N
Q
ANQ
A
NQ
passing through point
Q
Q
Q
. Prove that the lines
p
p
p
and
q
q
q
intersect on line
B
C
BC
BC
.
3
2
Hide problems
Q symmetric of P wrt BH wanted, orthocenter related
Given is an acute triangle
A
B
C
ABC
A
BC
. Point
P
P
P
lies inside this triangle and lies on the bisector of angle
∠
B
A
C
\angle BAC
∠
B
A
C
. Suppose that the point of intersection of the altitudes
H
H
H
of triangle
A
B
P
ABP
A
BP
lies inside triangle
A
B
C
ABC
A
BC
. Let
Q
Q
Q
be the intersection of the line
A
P
AP
A
P
and the line perpendicular to
A
C
AC
A
C
passing through
H
H
H
. Prove that
Q
Q
Q
is the point symmetrical to
P
P
P
wrt the line
B
H
BH
B
H
.
n persons a a party, everyone dislikes only 1
n
n
n
people met at the party, with
n
≥
2
n \ge 2
n
≥
2
. Each person dislikes exactly one other person present at the party (but not necessarily reciprocal, i.e. it may happen that
A
A
A
dislikes
B
B
B
even though
B
B
B
does not dislike
A
A
A
) and likes all others. Prove that guests can be seated at three tables in such a way that each guest likes all the people at his table.
2
2
Hide problems
number of positive divisors of n is second largest divisor of n.
For a positive integer
n
n
n
, let
d
(
n
)
d(n)
d
(
n
)
denote the number of positive divisors of
n
n
n
. Determine all positive integers
n
n
n
for which
d
(
n
)
d(n)
d
(
n
)
is the second largest divisor of
n
n
n
.
permutations of numbers 1-2023
The numbers
1
,
2
,
.
.
.
,
2023
1, 2,..., 2023
1
,
2
,
...
,
2023
are written on the board in this order. We can repeatedly perform the following operation with them: We select any odd number of consecutively written numbers and write these numbers in reverse order. How many different orders of these
2023
2023
2023
numbers can we get?Example: If we start with only the numbers
1
,
2
,
3
,
4
,
5
,
6
1, 2, 3, 4, 5, 6
1
,
2
,
3
,
4
,
5
,
6
, we can perform the following steps
1
,
2
,
3
,
4
,
5
,
6
→
3
,
2
,
1
,
4
,
5
,
6
→
3
,
6
,
5
,
4
,
1
,
2
→
3
,
6
,
1
,
4
,
5
,
2
→
.
.
.
1, 2, 3, 4, 5, 6 \to 3, 2, 1,4, 5, 6 \to 3, 6, 5, 4, 1, 2 \to 3, 6, 1, 4, 5, 2 \to ...
1
,
2
,
3
,
4
,
5
,
6
→
3
,
2
,
1
,
4
,
5
,
6
→
3
,
6
,
5
,
4
,
1
,
2
→
3
,
6
,
1
,
4
,
5
,
2
→
...
1
2
Hide problems
n-S(n), n+S(n) are both perfect squares
Let
S
(
n
)
S(n)
S
(
n
)
denote the sum of all digits of natural number
n
n
n
. Determine all natural numbers
n
n
n
for which both numbers
n
+
S
(
n
)
n + S(n)
n
+
S
(
n
)
and
n
−
S
(
n
)
n - S(n)
n
−
S
(
n
)
are square powers of non-zero integers.
AM_|_MD if BC = 2 AC, AD = 2BD, BM=//MC
Given a triangle
A
B
C
ABC
A
BC
,
B
C
=
2
⋅
A
C
BC = 2 \cdot AC
BC
=
2
⋅
A
C
. Point
M
M
M
is the midpoint of side
B
C
BC
BC
and point
D
D
D
lies on
A
B
AB
A
B
, with
A
D
=
2
⋅
B
D
AD = 2 \cdot BD
A
D
=
2
⋅
B
D
. Prove that the lines
A
M
AM
A
M
and
M
D
MD
M
D
are perpendicular.