2
Problems(2)
Easy perpendicularity
Source: Caucasus MO 2024, Juniors P2
3/15/2024
The rhombuses and are arranged so that lies on the segment and lies on the segment . Point is the midpoint of . Prove that .
geometry
Easy conditional geometry
Source: Caucasus MO 2024, Seniors P2
3/15/2024
In an acute-angled triangle let be the bisector, and let be the altitude. Let the lines and meet the circumcircle of again at and , respectively. Given that , prove that .
geometry