Let ABC be a triangle with circumcircle ω. The internal angle bisectors of ∠ABC and ∠ACB intersect ω at X=B and Y=C, respectively. Let K be a point on CX such that ∠KAC=90∘. Similarly, let L be a point on BY such that ∠LAB=90∘. Let S be the midpoint of arc CAB of ω. Prove that SK=SL. geometrygeometry proposed