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Problems
Contests
International Contests
Baltic Way
1995 Baltic Way
9
9
Part of
1995 Baltic Way
Problems
(1)
Prove sum
Source: Baltic Way 1995
10/8/2011
Prove that
1995
2
−
1994
3
+
1993
4
−
…
−
2
1995
+
1
1996
=
1
999
+
3
1000
+
…
+
1995
1996
\frac{1995}{2}-\frac{1994}{3}+\frac{1993}{4}-\ldots -\frac{2}{1995}+\frac{1}{1996}=\frac{1}{999}+\frac{3}{1000}+\ldots +\frac{1995}{1996}
2
1995
−
3
1994
+
4
1993
−
…
−
1995
2
+
1996
1
=
999
1
+
1000
3
+
…
+
1996
1995
induction
logarithms
algebra proposed
algebra