Let P and Q be points inside a triangle ABC such that ∠PAC=∠QAB and ∠PBC=∠QBA. Let D and E be the feet of the perpendiculars from P to the lines BC and AC, and F be the foot of perpendicular from Q to the line AB. Let M be intersection of the lines DE and AB. Prove that MP⊥CF perpendicularequal anglesgeometry