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Austrian-Polish
2005 Austrian-Polish Competition
4
4
Part of
2005 Austrian-Polish Competition
Problems
(1)
FLT fraction is a square
Source: Austrian-Polish 2005, Problem 4
7/5/2015
Determine the smallest natural number
a
≥
2
a\geq 2
a
≥
2
for which there exists a prime number
p
p
p
and a natural number
b
≥
2
b\geq 2
b
≥
2
such that
a
p
−
a
p
=
b
2
.
\frac{a^p - a}{p}=b^2.
p
a
p
−
a
=
b
2
.
fermat's little theorem
Perfect Squares
prime
number theory
Diophantine equation