Suppose ABCD is a square piece of cardboard with side length a. On a plane are two parallel lines ℓ1 and ℓ2, which are also a units apart. The square ABCD is placed on the plane so that sides AB and AD intersect ℓ1 at E and F respectively. Also, sides CB and CD intersect ℓ2 at G and H respectively. Let the perimeters of △AEF and △CGH be m1 and m2 respectively.
Prove that no matter how the square was placed, m1+m2 remains constant. geometryperimetercircumcircletrigonometrygeometric transformationrotationangle bisector